Question

check my answer, prime numbers

Answer 1

\(xyz \equiv 0 \mod x \implies xyz + 1 \equiv 1 \mod x\)

so,
\(xyz + 1\) is not divisible by \(x\)

similarly u can show its not divisible ny y or z aswell

Answer 2

btw, you're right !

Answer 3

alright, thank you

Answer 4

np :)