Mathematics
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OpenStudy (anonymous):
If f(x) = log3 (x + 1), what is f−1(2)?
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OpenStudy (anonymous):
the question is a little vague.. please specify
OpenStudy (anonymous):
1, 8, 10, or 27
OpenStudy (anonymous):
The answers are what I just typed, they are the ones to pick from atleast... I ma just utterly stuck on this equation.
OpenStudy (anonymous):
its okay. are you sure its asking for f-1(2)?
OpenStudy (anonymous):
no sorry hold on it's f^-1 (2)
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OpenStudy (anonymous):
hey i have that same problem
OpenStudy (anonymous):
.o. @naahhbass algebra two?
OpenStudy (anonymous):
yehh for my worksheet
OpenStudy (anonymous):
also is the 3 of log 3 the base or coefficient?
OpenStudy (anonymous):
base
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OpenStudy (anonymous):
see that changes the problem. give me a sec
OpenStudy (anonymous):
okki dokki
OpenStudy (anonymous):
okay so the answer is 1
OpenStudy (anonymous):
but here is how you get it:
calculating the log is not the problem. its how to to get to f^-1(2) that throws you off?
OpenStudy (anonymous):
yes it is
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OpenStudy (anonymous):
its simple. so if you look at f^-1(2).. you can also write it as \[\frac{ 1 }{ f(2) }\]
OpenStudy (anonymous):
so you just calculate f(2) as it is:
\[f(2)= \log_{3} (2+1)= \log_{3} 3 = 1 \]
OpenStudy (anonymous):
and 1/1 is 1
tadaaa c:
OpenStudy (anonymous):
Awesome thank you so very much!
OpenStudy (anonymous):
you are welcome