Ask your own question, for FREE!
Mathematics 24 Online
OpenStudy (anonymous):

The circle formed by the blades of a fan has a circumference of fifty-six and four-sevenths inches. What is its diameter? Use twenty-two sevenths for pi. twelve inches eighteen inches twenty-one inches twenty-six inches

OpenStudy (anonymous):

hello

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

still dont get it

OpenStudy (anonymous):

hello

OpenStudy (anonymous):

@nincompoop

OpenStudy (anonymous):

@Ashleyisakitty

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

@Zale101

OpenStudy (anonymous):

hello

OpenStudy (anonymous):

hello

OpenStudy (anonymous):

can u help

OpenStudy (doc.brown):

|dw:1393389383514:dw|

OpenStudy (anonymous):

wat am i lookin at

OpenStudy (doc.brown):

|dw:1393389488697:dw|

OpenStudy (doc.brown):

|dw:1393389519874:dw|

OpenStudy (doc.brown):

|dw:1393389538077:dw|

OpenStudy (doc.brown):

|dw:1393389581445:dw|

OpenStudy (anonymous):

wat r u doin?

OpenStudy (doc.brown):

|dw:1393389632505:dw|

OpenStudy (doc.brown):

the circumference of a circle is 2 times bigger than pi times the radius see?

OpenStudy (anonymous):

so wats the answer

OpenStudy (doc.brown):

the diameter is two times r so the circumference is pi times d

OpenStudy (doc.brown):

\[C=\pi d\]\[57=\frac{22}{17}d\]

OpenStudy (anonymous):

i need the answer pls

OpenStudy (doc.brown):

Sorry, I meant \[C=\pi d\]\[57=\frac{22}{7}d\]

OpenStudy (doc.brown):

You want the d by itself, try getting rid of the 7 first.

OpenStudy (anonymous):

i need the answer pls imma give you a metle

OpenStudy (anonymous):

medal*

OpenStudy (doc.brown):

The answer involves math. I'll give you a hint, what's \(\dfrac{7}{7}\)?

OpenStudy (anonymous):

wat?

OpenStudy (anonymous):

can u help

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!