Question

Please help solve \[(\frac{1}{6})^{-p}=(\frac{1}{36})^{p}\].

Answer 1

i guess \(p=0\)

Answer 2

\(\frac{1}{36}=(\frac{1}{6})^2\) so you have
\[p=-2p\]

Answer 3

I guess it doesn't say, it just says to solve the equation

Answer 4

which means \(p=0\)

Answer 5

i know it has to do with base changes

Answer 6

i wrote the reasoning above
did you understand what i wrote?

Answer 7

\[\frac{1}{36}=(\frac{1}{6})^2\] so
\[(\frac{1}{36})^p=(\frac{1}{6})^{-2p}\]

Answer 8

i need to solve to figure out what p is equal to but I don't know how you got p=0

Answer 9

the equation becomes \(-2p=p\) which is only true if \(p=0\)

Answer 10

i see, thank you!