Graphing Operations
1 :) do you want me to explain this one?
ya if you dont mind
i would love to learn
haha ok :) Look at the equation 3x+2=y ; y=5 the equation says that y=5 so you plug it into the y spot giving you: 3x+2=5
ok i understand that
now make a function :) do you know how to do that?
i was watching you explain it and taking notes
Ok, great :) so, we start at the first equation and ignore the fact that it says "y=5" giving us 3x+2=y and we write|dw:1393386615769:dw|
all this means is that if x=1 y has to equal 5 or if y=5 then x has to equal 1 :) and if x=2 then y=8 and so on and so forth, do you see how to do it now?
oh ok so its basically multiplying
kind of... let's pick up where we left off :) 3x+2=5 ... now we subtract 2 on both sides of the equation giving us 3x=3
so it gave me the answer of 3
nope now we do this...\[\frac{ 3x }{ 3 }=3\]
the 3's on the left side
cancel out and the three on the left becomes 1 because 3 divided by 3 is 1 :)
\[\frac{ 3x }{ 3 }= \frac{ 3 }{ 3 }\]
u r very good at this
haha I guess :) I used to be very confused when it came to this then I just practiced and started to get the hang of it. :) this is my second year in algebra :)
but I guess it helps when you think math is fun lol :)
lol ya or if youre just awesome like u
oh wait so its 1
haha yes it is 1 :) so to sum it up all we did was substitute y in for 5 giving us 3x+2=5 and then we think what times 3 gives us a number that can be added to 2 and give us 5.
does that make it easier to understand? :)
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