Question

can someone help me isolate g?

Answer 1

\[T=2\pi \sqrt{L/g}\]

Answer 2

\[\frac{T}{2\pi}=\sqrt{\frac{L}{g}}\] is a start
then square both sides

Answer 3

i did that then you have L/g
what is next

Answer 4

flip it

Answer 5

\[\frac{T^2}{4\pi^2}=\frac{L}{g}\]
\[\frac{4\pi^2}{T^2}=\frac{g}{L}\]

Answer 6

then multiply both sides by \(L\)

Answer 7

are you sure you can just flip it?

Answer 8

i can if i want

Answer 9

Yes you can.

Answer 10

thanks

Answer 11

or you can solve always\[\frac{a}{b}=\frac{c}{x}\] for \(x\) vial
\[x=\frac{bc}{a}\]

Answer 12

They are still equal
\[\frac{1}{2}=\frac{2}{4}\]\[\frac{2}{1}=\frac{4}{2}\]

Answer 13

ok ill try it thanks

Answer 14

\[((2\pi)^{2}/T ^{2})L=g\]

Answer 15

is this right