Question

1/729=243^6t-4

Answer 1

Hi. You can express 1/729 as\[3^{-6}\]and 243 as\[3^5\]Does that help?

Answer 2

\[\frac{ 1 }{ 729} = 243^6t-4\]
or
\[\frac{ 1 }{ 729 }=243 ^{6t} -4?\]

Answer 3

@timaashorty My best assumption is\[243^{6t - 4}\]

Answer 4

im having a hard time making it look right, yes parthKohli that's it

Answer 5

@ParthKohli I really don't understand

Answer 6

OK, let me explain. To solve equations like this when the variable is in the power, you can express both the numbers in both the sides with exponents of the same number. For example, if you are to solve\[27 = (1/3)^{x}\]Then first express both 27 and 1/3 with the powers of the same number. Here, we can express 27 as \(3^3\) and \(1/3\) as \(3^{-1}\). Now, we have\[3^3 = (3^{-1})^x\]\[\Rightarrow 3^3 = 3^{-x}\]But if both of these are equal, then the exponents must be equal too! So\[3^3 = 3^{-x} \Rightarrow 3 = -x\Rightarrow x=-3\]

Answer 7

Does the original question make sense to you now?

Answer 8

yes thank you very much

Answer 9

what is your ans?