Question

Subtract:

Answer 1

Get common denominators.

Answer 2

this might sound dumb but... how exactly do I do that??

Answer 3

Apply the basic fraction rules you learned.

Answer 4

Yeah that's what I am confused about..... Can you explain how?

Answer 5

Here use this formula :)
\[\large \frac{ a }{ b } + \frac{ c }{ d } = \frac{ ad + bc }{ bd }\]

Answer 6

^Yea, pretty much that

Answer 7

\[\frac{ 5 }{ x-2 } + \frac{ 3 }{ x+2 } = \frac{ 5(x+2) + 3(x-2) }{ (x-2)(x+2) }\]

Answer 8

8x+4/ (x-2)(x+2) ??

Answer 9

Think of it this way, say we have:
\[\LARGE \frac{1}{3}+\frac{2}{5}\]
How could we add them? Get common denominators:
\[\LARGE \frac{1}{3}*\frac{5}{5}+\frac{2}{5}*\frac{3}{3}\]
Now we can add them:
\[\LARGE \frac{5}{15}+\frac{6}{15}\]
Same with yours,,

Answer 10

Thank you @AshleyAlley<3 T_T

Answer 11

Okay so was my answer correct? I get it now

Answer 12

Yea, it's right.

Answer 13

Oh, wait your original question was to subtract them not add, ahhhh my bad >.<

Answer 14

\[\frac{ 5 }{ x-2 } - \frac{ 3 }{ x+2 } = \frac{ 5(x+2)- 3(x-2) }{ (x-2)(x+2) }\]

Answer 15

you're welcome @Luigi0210 xD