You have a solution made of 300 grams of ethanol (C2H5OH) and 500 grams of water. What is the mole fraction of ethanol in this solution? (Points : 1) 0.19 M 0.81 M 0.19 0.81
If you want to make 0.5 L of a 0.01 M solution of bromine (Br2) in water, how much bromine would you need? (Points : 1) 0.8 grams 0.8 moles 1.6 grams 1.6 moles Question 2.2. Which of the following statements is the correct definition of molarity? (Points : 1) number of moles of solvent/liter solution number of grams of solvent/liter solution number of moles of solute/liter solution number of grams of solute/liter solution
the last one is \[M=\frac{ moles of solute }{ Liters of solution }\]
so its C
yes.
Thank you
for the other two, its just about the same concepts. do you know how to use the molar mass to convert to moles?
no i dont
okay well this should help: \[grams of substance*\frac{ moles of substance }{ molar mass of substance }\]
do you know what the molar mass is?
the mass of a substancd
the mass of a substance per one mole. you get the molar mass by using the periodic table of elements
ok thanks
if you use the equation i gave you to convert, then those other two problems should be a breeze.
alright i will if i need any help ill ask :)
ok
I dont know the first one but for the second one i got B is that righ?
very close but not quite. \[M=\frac{ mol solute }{ L solution }\]
so....\[0.01=\frac{ x moles }{ .5 L }\]
x moles = 0.005 moles Br2
but that isnt one of the options so we need to go farther. (0.005 mol)(159.808g/1 mol) "mol" cancels and we are left with 0.8 grams Br2
Ohhh okay. what about the other one
use the molar mass to convert both substances to moles first.
Ethanol: (500g)(1 mol/46.07g) 10.85 mol ethanol
can you do the other one?
no i dont understand it
its thesame thing that i just did. with ethanol
with the what? sorry im confused
sometimes its easier to see it written.... does this help?
yes i skipped over the water part thats why i didnt understand
okay. so do you know what a mole fraction is?
no
\[\frac{ moles-of-substance }{ total-number-of-moles }\]
so... we want this: \[\frac{ moles-of-ethanol }{ (moles-of-ethanol)+(moles-of-water) }\]
so the answer is .19m
yes!
Yayyy thank you
do you understand it? like maybe with a bit of practice, you could do it on your own next time?
yea i think so
good. :)
Join our real-time social learning platform and learn together with your friends!