Does no one really know this? A 190 ft tower is located on the side of a mountain that is inclined 19° to the horizontal. A guy wire is to be attached to the top of the tower and anchored at a point 42 ft downhill from the base of the tower. Find the shortest length of wire needed.
I'll give it a crack. Would you prefer it solved with triangles or vectors?
triangles plz
k gimme a sec :)
this is gonna come in parts: |dw:1393398073952:dw|
so first you want to make a right triangle out of the problem. it just makes the math much nicer. Next step is to solve for x, the base of the triangle (which i forgot to label) and then use pythagorean theorem to find the length of wire required
so x = 42sin(19) the base we'll call b =42cos(19) then pythagorean theorem states that y^2 = (190+x)^2 + b^2 so y = sqrt((190+x)^2 + b^2)
oh...makes sense now
i got confused by the guy wire part, like i wasnt sure which one was the guy wire
i thought the middle line was the guy wire
alright tyvm for the help :P
no worries :)
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