Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (awy):

Does no one really know this? A 190 ft tower is located on the side of a mountain that is inclined 19° to the horizontal. A guy wire is to be attached to the top of the tower and anchored at a point 42 ft downhill from the base of the tower. Find the shortest length of wire needed.

OpenStudy (awy):

OpenStudy (anonymous):

I'll give it a crack. Would you prefer it solved with triangles or vectors?

OpenStudy (awy):

triangles plz

OpenStudy (anonymous):

k gimme a sec :)

OpenStudy (anonymous):

this is gonna come in parts: |dw:1393398073952:dw|

OpenStudy (anonymous):

so first you want to make a right triangle out of the problem. it just makes the math much nicer. Next step is to solve for x, the base of the triangle (which i forgot to label) and then use pythagorean theorem to find the length of wire required

OpenStudy (anonymous):

so x = 42sin(19) the base we'll call b =42cos(19) then pythagorean theorem states that y^2 = (190+x)^2 + b^2 so y = sqrt((190+x)^2 + b^2)

OpenStudy (awy):

oh...makes sense now

OpenStudy (awy):

i got confused by the guy wire part, like i wasnt sure which one was the guy wire

OpenStudy (awy):

i thought the middle line was the guy wire

OpenStudy (awy):

alright tyvm for the help :P

OpenStudy (anonymous):

no worries :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!