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Mathematics 13 Online
OpenStudy (anonymous):

Suppose that the functions p and q are defined as follows: p(x)=-2x+1 q(x)=-x^2 Find the following p o q(-5)=10x^3 q o p(-5)=2x^3-5 Iis this right?

Parth (parthkohli):

Hmm... you've reversed the two answers, I suppose!

Parth (parthkohli):

But that isn't correct either. Well, let's approach this step-by-step!

Parth (parthkohli):

You need to find p of q of -5. Or,\[p(\color{blue}{q(-5)})\]So, we first find what q(-5) is -- then we do the \(p\) of that.

OpenStudy (anonymous):

so, 5x^2-2x?

Parth (parthkohli):

Yeah, but you are not to find p o q (x), but p o q (-5).

OpenStudy (anonymous):

so p o q(-5) isn't -2x-1*(-x^2(-5) and q o p isn't -x^2(-2x-1(-5))?

Parth (parthkohli):

Hmm, not really. p o q(-5) means \(p(\color{blue}{q(-5)})\). So what this means is: First, find q(-5). Then, find the p of what you get.

Parth (parthkohli):

q(-5) is when you plug in -5 instead of \(x\).

Parth (parthkohli):

Are you following it?

OpenStudy (anonymous):

I don't think so. what would it look like?

Parth (parthkohli):

\[q(\color{blue}x) =-\color{blue}x^2\]\[q(-5) = -(-5)^2\]

Parth (parthkohli):

Does that make sense?

OpenStudy (anonymous):

so the answers would be poq(-5) 25-2x and 2x^2+1 qop(-5)

Parth (parthkohli):

Again, remember that it is not poq(x), but poq(-5).

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