What is the function shown in the graph:
A. f(x)=1/x+1 B. f(x)= x+1/x^2+3x+2 C. f(x)= x+2 D. f(x)= x^2+3x+2/x+1
Since there is a break at x=-1, you know that at some point there must be a divide by 0. The function is otherwise linear so you need a rational function with a numerator whose degree is one larger than its denominator. The only answer where this is the case is D. To prove it, you can factor out the numerator x^2+3x+2 into (x+2)(x+1) Notice how there is also an x+1 in the denominator. those cancel, but in order to keep the function the same, you must ensure that you keep the x=/= -1 (as that would result in a divide by zero. Hence, the function x^2+3x+2/x+1 simplifies to x+2; x=/=0
Oh okay thank you for explaining! (:
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