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Mathematics 16 Online
OpenStudy (blondisaurus):

Quick Question about imaginary numbers in comment section!

OpenStudy (blondisaurus):

\[Does \sqrt{3}i ^{2} equal -\sqrt{3}?\]

OpenStudy (blondisaurus):

Also what i^-7 simplify to?

ganeshie8 (ganeshie8):

\(i^2 = -1\)

ganeshie8 (ganeshie8):

you need to remember that

ganeshie8 (ganeshie8):

and yes, \(\large \sqrt{3} i^2 = \sqrt{3} (-1) = -\sqrt{3}\)

ganeshie8 (ganeshie8):

\(\large i^{-7} = \frac{1}{i^7} = ?\)

OpenStudy (blondisaurus):

1/ -1 + i?

OpenStudy (blondisaurus):

or 1/-i?

ganeshie8 (ganeshie8):

yes, \(\large i^{-7} = \frac{1}{i^7} = \frac{1}{(i^2)^3i} = \frac{1}{(-1)^3i} = \frac{1}{-i}\)

ganeshie8 (ganeshie8):

but nobody likes "i" in the denominator, so multiply top/bottom by i

ganeshie8 (ganeshie8):

\(\large \frac{1}{-i} \times \frac{i}{i} = \frac{i}{-i^2} = i\)

OpenStudy (blondisaurus):

Are both correct though? Could it be left as is?

ganeshie8 (ganeshie8):

technically, both are same and correct.

ganeshie8 (ganeshie8):

but every one prefers "i"'s in the top oly

OpenStudy (blondisaurus):

Oh okay. Thank you!!

ganeshie8 (ganeshie8):

think of it as rationalizing the denominator, nobody wants radicals left in the denominator (for no particular reason ofc )

ganeshie8 (ganeshie8):

u wlc :)

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