Mathematics
16 Online
OpenStudy (blondisaurus):
Quick Question about imaginary numbers in comment section!
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (blondisaurus):
\[Does \sqrt{3}i ^{2} equal -\sqrt{3}?\]
OpenStudy (blondisaurus):
Also what i^-7 simplify to?
ganeshie8 (ganeshie8):
\(i^2 = -1\)
ganeshie8 (ganeshie8):
you need to remember that
ganeshie8 (ganeshie8):
and yes,
\(\large \sqrt{3} i^2 = \sqrt{3} (-1) = -\sqrt{3}\)
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
\(\large i^{-7} = \frac{1}{i^7} = ?\)
OpenStudy (blondisaurus):
1/ -1 + i?
OpenStudy (blondisaurus):
or 1/-i?
ganeshie8 (ganeshie8):
yes,
\(\large i^{-7} = \frac{1}{i^7} = \frac{1}{(i^2)^3i} = \frac{1}{(-1)^3i} = \frac{1}{-i}\)
ganeshie8 (ganeshie8):
but nobody likes "i" in the denominator,
so multiply top/bottom by i
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
\(\large \frac{1}{-i} \times \frac{i}{i} = \frac{i}{-i^2} = i\)
OpenStudy (blondisaurus):
Are both correct though? Could it be left as is?
ganeshie8 (ganeshie8):
technically, both are same and correct.
ganeshie8 (ganeshie8):
but every one prefers "i"'s in the top oly
OpenStudy (blondisaurus):
Oh okay. Thank you!!
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
think of it as rationalizing the denominator,
nobody wants radicals left in the denominator (for no particular reason ofc )
ganeshie8 (ganeshie8):
u wlc :)