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Chemistry 9 Online
OpenStudy (rane):

How would you identify the empirical formula of a compound CuCla bH2O. You have at your disposal, an electronic balance and any other equipment you may need.

OpenStudy (rane):

i just need the steps of how to find it

OpenStudy (kewlgeek555):

Haven't learned about this yet, but thank you for calling me, and I hope someone helps you soon. Good luck! ;D

OpenStudy (***[isuru]***):

can we use other chemicals for this ? or we can only use equipment s ?

OpenStudy (rane):

we can use other chemicals as well

OpenStudy (rane):

thankx @kewlgeek555

OpenStudy (***[isuru]***):

i think we can do it this way.. first we measure the initial mass ( m1) second we heat it up to 100o C this will remove the H2O in the sample now we measure the mass again (m2) the amount of H20 = ( m1 -m2)

OpenStudy (rane):

can u write down the equation as well as u go

OpenStudy (***[isuru]***):

\[CuCl_{a}.bH_{2}O \rightarrow CuCl_{a} + bH_{2}O_{g}\] this happens on heating.. now only CuCl_a is remaining... and there r 2 ways.. and i dont know exactly which method u want ..so i will explain both methods

OpenStudy (rane):

just go with the one where water evaporates and then we r left with CuCla

OpenStudy (***[isuru]***):

first method is u react the CuCl_ a with NaOH

OpenStudy (rane):

wht if i react with K instead of NaOH

OpenStudy (***[isuru]***):

OH!.. u r going to a displacement reaction .... \[K + CuCl_{a} \rightarrow Cu + aKCl\] u mean this ?

OpenStudy (rane):

yup

OpenStudy (***[isuru]***):

then u r going to measure the amount of Cu formed ?

OpenStudy (rane):

yup

OpenStudy (***[isuru]***):

kk ... if u do that u can find the no. of moles of Cu in m2 mass of CuCl_a so...from that u can find the mass of Cl_a in it and them find the no. of moles in Cl which is a

OpenStudy (rane):

yup thanks thats wht i got just wanted to ma

OpenStudy (***[isuru]***):

kk... i was going to form a precipitate using NaOH... guess my method was longer :(

OpenStudy (rane):

oh no..... thanks i have test so i have to study for it no longer methods thank you!!!

OpenStudy (***[isuru]***):

u r welcome :p

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