Question

At time t1=12 s, a car is located at ⟨107,0,0⟩ m and has velocity ⟨5,0,0⟩ m/s. At time t2=16 s, what is the x component of the position of the car (in meters)?

Answer 1

\[x2=(127,0,0)\]i think:\[\Delta x/\Delta t=v\]\[\Delta x=4(5,0,0)\]\[\Delta x=(20,0,0)\]

x2=(127,0,0)

Answer 2

Thanks !

Answer 3

Question 5
Here are the positions at three different times for a bee in flight (a bee's top speed is about 7 m/s).
time 5.4 s 5.9 s 6.4 s
position ⟨−3.9,0,0⟩ m ⟨−1.4,0,0⟩ m ⟨0.6,0,0⟩ m

(a) Compute the bee's average velocity between 5.4 s and 5.9 s. Be careful with signs.
What was the x component of the bee's average velocity (in m/s) between 5.4 s and 5.9 s?

Answer 4

@fazeli

Answer 5

like up , we have:\[\Delta x /\Delta t=v\]\[\frac{ -1.4-(-3.9) }{ 5.9-5.4 }=5 m/s\]

Answer 6

Thanks !

Answer 7

finish?

Answer 8

Compute the bee's average velocity between 5.4 s and 6.4 s.
What was the x component of the bee's average velocity (in m/s) between 5.4 s and 6.4 s?
Answer for Question 8

Answer 9

Last one !

Answer 10

like up:\[\frac{ 0.6-(-3.9) }{ 6.4-5.4 } =v=4.5 m/s\]