Question

t^2(t+1)-t(2t^2-1) simplify & write in standard form

Answer 1

First, use the distributive property for both sets of parentheses.

Answer 2

then what? @mathstudent55

Answer 3

the answer to the question is t^3 +t^2 - t

Hope it helped

Answer 4

I need it explained not just the answer @ajindalaisj

Answer 5

ok i will elaborate

t^2(t+1)-t(2t^2-1)
=t^3+t^2-2t^3-t
now you combine the like terms
=-t^3+t^2-t

Hope it helped

Answer 6

are you sure this is the correct way to work it out? @ajindalaisj

Answer 7

Yes @pop101 I am 100% sure about that question. Its middle school stuff

Answer 8

\(t^2(t + 1) - t(2t^2 - 1)\)

You need to use the distributive property for each set of parentheses. For the first set of parentheses it's pretty straightforward. For the second set of parentheses, remember that the negative sign outside (with the -t) will change all the signs inside the parentheses once you multiply it out.

\(t^2(t + 1) - t(2t^2 - 1)\)

\(= t^2 * t + t^2 * 1 - t * 2t^2 - t * (-1) \)

\(= t^3 + t^2 - 2t^3 + t\)

Now we combine like terms:

\(= -t^3 + t^2 + t\)

It's in standard form because the exponent of t is in descending order.

Answer 9

@ajindalaisj wrote:

"the answer to the question is t^3 +t^2 - t

Hope it helped

ok i will elaborate
t^2(t+1)-t(2t^2-1)
=t^3+t^2-2t^3-t
now you combine the like terms
=-t^3+t^2-t

Yes pop101 I am 100% sure about that question. Its middle school stuff"

The correct answer is:

-t^3 + t^2 + t

Notice the +t at the end.

Be careful with the multiplication of signed numbers.
-t * (-1) = t, not -t
Also, even a math professor can make a mistake in simple arithmetic, so be careful when you say you're 100% sure and it's simply middle school stuff.