Question

How do I find the missing value ?

Answer 1

\(\bf tan(\square )=38\implies tan^{-1}[tan(\square )]=tan^{-1}(38)\implies \square =tan^{-1}(38)\)

Answer 2

wait im confused :/

Answer 3

... ok where?

Answer 4

the whole equation you put up there

Answer 5

do you know what an inverse function is? like say \(\bf sin^{-1}\qquad cos^{-1}\qquad tan^{-1}\quad ?\)

Answer 6

no

Answer 7

do you happen to have them in your calculator btw? do you see any buttons with those labels \(\bf [sin^{-1}]\qquad [cos^{-1}]\qquad [tan^{-1}]\quad ?\)

Answer 8

yes

Answer 9

i guess that im just having trouble understanding how to find the missing value exactly i dont know if you can understand what im trying to say

Answer 10

ok well \(\bf sin^{-1}({\color{red}{ whatever}})\implies \textit{what is the angle WHOSE sine is }{\color{red}{ whatever}}
\\ \quad \\
cos^{-1}({\color{red}{ whatever}})\implies \textit{what is the angle WHOSE cosine is }{\color{red}{ whatever}}
\\ \quad \\
tan^{-1}({\color{red}{ whatever}})\implies \textit{what is the angle WHOSE tangent is }{\color{red}{ whatever}}\)

Answer 11

\(\bf tan({\color{red}{ angle}})={\color{blue}{ value}}\implies tan^{-1}({\color{blue}{ value}})={\color{red}{ angle}}
\\ \quad \\
tan^{-1}[tan({\color{red}{ angle}})]={\color{red}{ angle}}\)

Answer 12

thus \(\bf tan(\square )=38\implies tan^{-1}[tan(\square )]=tan^{-1}(38)\implies \square =tan^{-1}(38)\)

Answer 13

god i dont know if im slow today or you're not very good explaining this whatever it is im not getting it

Answer 14

nevermind i think i get it now lol