Question

Solve this equation... ∫xe^-x^2 dx??? I WILL GIVE OUT A MEDAL TO WHOEVER CAN HELP!

Answer 1

u=-x^2
du=-2x dx

Answer 2

Only one person gets a medal sorry it won't let me do more than one.

Answer 3

Troll????

Answer 4

so
\(\frac{-1}{2}\int e^u du=-\frac{1}{2}e^u+c=-\frac{1}{2}e^{-x^2}+c\)

Answer 5

No...

Answer 6

Why are you calling me a troll you idiot?

Answer 7

dont worry about them, focus on me:) do you understand what I did?

Answer 8

Yes. kinda.

Answer 9

You called me a troll

Answer 10

No i did not..

Answer 11

on my page you did

Answer 12

DID NOT. I DONT EVEN KNOW YOU. WTF..

Answer 13

let \(u=-x^2\) then \(\frac{du}{dx}=-2x\)
so
\(dx=\frac{du}{-2x}\) plug this into your integral
\(\int xe^{-x^2}dx=\int xe^u \frac{du}{-2x}=-\frac{1}{2}\int e^udu=-\frac{1}{2}e^u+c\)
plugging back in for \(u\) we get
\(\int xe^{-x^2}dx=-\frac{1}{2}e^{-x^2+c}\)

Answer 14

that should say
\(\int xe^{-x^2}dx=-\frac{1}{2}e^{-x^2}+c\)

Answer 15

do you understand?

Answer 16

Yup :)