Question

Limits help, confused.

Answer 1

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Answer 2

i like ur heair

Answer 3

ME TO

Answer 4

It looks like you just divide the areas.

Answer 5

To find the area of the triangle :
Draw perpendicular from the top left corner to the right side.
Using trigonometry,
length of perpendicular = 10 sin θ
base = 10
B(θ) = 1/2 * base * height = 50 sin θ

To find the area of the semicircle :
From the bottom vertex, draw perpendicular to the top edge of the triangle.
Angle between this line and one of the sides = θ/2.
Radius of semicircle = 1/2 * top edge = 10 sin(θ/2)
A(θ) = 1/2*pi*radius^2 = 50*pi*sin^2(θ/2)

A(θ) / B(θ) = pi*sin^(θ/2) / sin θ
Put sinθ = 2sin(θ/2)cos(θ/2)
A(θ) / B(θ) = pi*sin(θ/2) / 2cos(θ/2) = pi*tan(θ/2)/2

As θ -> 0, tanθ/2 -> 0

So A/B -> 0

Answer 6

That was actually right, thanks xD

Answer 7

ur welcome