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Mathematics 10 Online
OpenStudy (anonymous):

6 – 4(3 – 5) + 30 ÷ 5 I need helpn working this out!

OpenStudy (opcode):

Use BODMAS: Brackets Orders Division Multiplication Addition Subtraction

OpenStudy (opcode):

\(6 – 4(3 – 5) + 30 ÷ 5 \implies 6 – 4(–2) + 30 ÷ 5\) (Brackets). No orders so now we do division. \(6 – 4(–2) + 30 ÷ 5 \implies 6 – 4(–2) + 6\) (Division). Can you continue from there @justdechea ?

OpenStudy (opcode):

@gabby16404 How did you get that? (It is not correct.)

OpenStudy (littlebird):

PEMDAS is better Parentheses Exponents Multiplication Division Addition Subtraction

OpenStudy (anonymous):

6 – 4(3 – 5) + 30 ÷ 5 6 – 4(–2) + 30 ÷ 5 6 – 4(−4) + 30 ÷ 5 6 + 16 + 30 ÷ 5 6 + 16 + 6 22 + 6 28 @Opcode is thisright?

OpenStudy (opcode):

No. Let me show you one more step. We just did division according to BODMAS next is multiplication. \[6–4(–2)+6\implies 6 - (-8) + 6\] We know because of basic arithmetic that a negative and negative make positive. So: \[6 + 8 + 6\]

OpenStudy (anonymous):

I under stand now @Opcode the (-2) comfused me a little

OpenStudy (opcode):

No problem let me explain that part some more though :-). \[4(-2)\] Really means: \[4 \times (-2)\] Which makes: \[-8\] And since we had: \[6 - 4(-2)\] It really means: \[6 - -8\] And a negative and negative make positive so: 6 + 8

OpenStudy (anonymous):

thanks

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