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Mathematics 10 Online
OpenStudy (anonymous):

solve this integral showing steps

OpenStudy (anonymous):

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zepdrix (zepdrix):

\[\Large\bf\sf \int\limits \frac{\sec^2\sqrt{x}}{\sqrt{x}}\;dx\quad=\quad \int\limits \sec^2\color{royalblue}{\sqrt{x}}\left(\frac{1}{\sqrt{x}}\;dx\right)\] Let \(\Large\bf\sf u=\sqrt{x}\) Replacing only \(\Large\bf\color{royalblue}{\text{ this one}}\).

zepdrix (zepdrix):

Find du, the other sqrtx will be part of it.

zepdrix (zepdrix):

Do you remember the derivative of \(\Large\bf\sf \sqrt x\) ? It's a good one to have memorized, shows up a lot. Doing the power rule is kind of a burden, but you can do that if you need.

OpenStudy (anonymous):

1/2 root x

zepdrix (zepdrix):

\[\Large\bf\sf du=\frac{1}{2\sqrt x}dx\]Ok good. We're not able to substitute this in just yet. That 2 is causing trouble. Hmmm what can we do?

OpenStudy (anonymous):

distribute ?

zepdrix (zepdrix):

? :O Does distribute meannnn multiply?

zepdrix (zepdrix):

I'm not sure if that's what you meant to say or not lol but yes, we want to multiply the 2 to the other side.

OpenStudy (anonymous):

no I ment like factor it from the integral sign ??

zepdrix (zepdrix):

\[\Large\bf\sf 2du=\frac{1}{\sqrt x}dx\]

OpenStudy (anonymous):

|dw:1393477538305:dw|

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