Question

Find an equation of the line containing the point (–2, –5) and parallel to the line 4x–5y=13

Answer 1

Have you considered calculating the slope of the given line?

Answer 2

honestly i really dont even know where to start

Answer 3

I do not believe that. Have you heard of the "Slope Intercept Form"?

Answer 4

no i havent :/

Answer 5

How about "Point-Slope" form?

Answer 6

yes ive heard of that one

Answer 7

Can you write it, here? What does it look like and what does it mean?

Answer 8

y – y1 = m(x – x1) When i have a point from the graph and plug it into the slope

Answer 9

am i right?

Answer 10

Yes. Very good. Can you put the GIVEN line into this form?

Answer 11

ok so is it?:y– –5= 5/4 (x– –2)

Answer 12

1) We don't know that the given line passes through (-2,-5). Most likely, it doesn't.
2) We actually don't care, since all we needed was the slope, 4/5 (be more careful).
3) Using the Point-Slope Form, we have...

(y-(-5)) = (4/5)(x-(-2))

or

(y+5) = (4/5)(x+2)

Answer 13

oh ok thanks... so what would be the next step?

Answer 14

None. It is done.