Question

Improper Integral
0∫-inf(1/(2x-1)^2))

Answer 1

\[\Large\bf\sf \int\limits_{-\infty}^0 \frac{1}{(2x-1)^2}dx\]Mmmm ok what part you having trouble with?

Answer 2

\[\Large\bf\sf \int\limits\limits_{-\infty}^0 \frac{1}{(2x-1)^2}dx\quad = \quad \int\limits\limits_{-\infty}^0 (2x-1)^{-2}dx\]

Answer 3

Power Rule for Integration.
If the 2x is confusing you, you can do a `u-sub` I guess.

Answer 4

Thanks zepdrix