Question

Can you explain me how to solve: 7log9 (x + 8) = 7.

Answer 1

\[\log9(x+8)=1\]

Answer 2

\[9(x+8)=e ^{1}\]

Answer 3

\[9x+72=e ^{1}\]

Answer 4

can you please explain me the second step ?

Answer 5

is 9 is the base of the log or is it just num multipl to (x+8) ?

Answer 6

it is the base

Answer 7

so esam take care of the base e wont help

Answer 8

the 9 is the base?
so my ans/ is not correct

Answer 9

yess

Answer 10

so how can it be solved, can you help me please this topic really confuses me

Answer 11

use this hint :
log x for base b =y
b^y=x

Answer 12

7log9 (x + 8) = 7.
log9 (x+8)=1
using the hint
9^1=x+8

Answer 13

so u have
x+8=9
x=1
hope ur getting it nw

Answer 14

thank you !!

Answer 15

np , ur wlc ^^