If the hypotenuse of a 45-45-90 triangle is 5 sqrt 3 how do I find the two legs?
oke how long is the hypotenuse
All i need is the hypotenuse then i will have the rest for you
the hypotenuse is 5 square root three
ok
125 2√ 2 heres one
its the same for both
I understand its the same but how do I get those two leg answers?
as two sides have same angle (45,45) so these have the same length so let hypotenuse = z 1st leg = x 2nd leg = y from pythagoras theorem \[z^2 = x^2 + y^2\] as x = y {same angles} so \[z^2 = x^2 + x^2\] \[z^2 = 2x^2\] putting the values \[( 5 \sqrt{3} )^2 = 2x^2\] 25(3) = 2x^2 75 = 2x^2 75/2 = x^2 \[\sqrt{37.5} = x \] So \[1st leg = \sqrt{37.5} \] \[2nd leg = \sqrt{37.5} \]
Wow. That's kinda confusing but I think I understand it a little bit better. Thank you very much
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