Question

What is the solution of the equation?
10 + sqrt x + 8 = -4

A. 44
B. 28
C. -2
D. 36

Answer 1

\[10+\sqrt{(x+8)}=-4\]or

\[10+\sqrt{x}+8=-4\]

Answer 2

the second one @KinzaN

Answer 3

Then you begin by subtracting 10 and then 8 from both sides:
\[10 -10 +\sqrt{x} +8 -8 = -4 - 10 - 8\]

Answer 4

Okay, I don't get the -10 and -8 under the -4.. Do I have to subtract both from the -4?

Answer 5

@KinzaN

Answer 6

If your question looks like the second one I posted, then you have to subtract 10 and 8 from both sides to "move" the numbers over to isolate for "x"

Answer 7

Haha, oh okay.

Answer 8

That makes more sense. \[-10+\sqrt{x+8}=-4\]

Answer 9

Sorry, I just get confused by all the parenthesis and all.

Answer 10

So you have to add 10 to both sides as a first step, following the rules of BEDMAS (but backwards) to isolate for "x" that's under the root.

Answer 11

I have to add 10 to 10 and 8 or the 10 and -4? and what's BEDMAS? lol

Answer 12

\[-10+(10)+\sqrt{x+8}=-4 +(10)\]

Answer 13

Well you're isolating for x, right? So the order of operations you're following are:
BEDMAS...

Brackets
Exponents
Division
Multiplication
Addition
Subtraction

but backwards!--so "SAMDEB"

Answer 14

Meaning you do your addition/subtraction first, then multiplication/division, followed by exponents and then brackets.

Answer 15

so that would be sqrt x + 8 = 6

Answer 16

\[(\sqrt{x+8})^{2} = 6^{2}\] \[x+8-(8)=36-(8)\]
\[x=28\]

Answer 17

Yeah! :D

Answer 18

Oh!! Thanks! How did you get the ^2? was it because of the parenthesis? :)