Question

Triangle STU is located at S (2, 1), T (2, 3), and U (0, -1). The triangle is then transformed using the rule (x-4, y+3) to form the image S'T'U'. What are the new coordinates of S', T,' and U'? Describe what characteristics you would find if the corresponding vertices were connected with line segments.

S = (2, 1)
T = (2, 3)
U = (-1, 0)

S' = (-2, 4)
T' = (-2, 6)
U' = (-5, 3)

Answer 1

@kewlgeek555

Answer 2

"Describe what characteristics you would find if the corresponding vertices were connected with line segments."
is the only part I need help with

Answer 3

Not good at this. >.<
Only equations.

@agent0smith @mathmale @ganeshie8

Answer 4

original co-ordinates are: S (2, 1), T (2, 3), and U (0, -1)
New coordinates would be
S'= (x-4, y+3) =(2-4,1+3) =(-2,4)
T'= (x-4, y+3) =(2-4,3+3) =(-2,6)
U'= (x-4, y+3) =(0-4,-1+3) =(-4,2)
Characteristics: In all i.e. S', T' U' all x-coridinates are -ve and y cordinates are +ve
hence they have been shifted in 2nd quadrant.

@CaseyCarns

Answer 5

Thank you so much! Do you mind if I tag you in a few more that I don't understand?