Question

What is the solution to the following system of equations?
-8x + 8y = -16
2x + 6y = -28
please help me( please break it down in steps please)

Answer 1

lets take
-8x + 8y = -16 ------ (1)
and
2x + 6y = -28 -----(2)

NOW lets multiply (2) by 4
u will get
(2) x 4
8x + 24y = - 112----- (3)

then add
(3) + (1)
-8x + 8y + 8x + 24y = -16 + (-112)

-8x will cancel out +8x and it will give u

32y = -128
y = -128/32
y = -4

now lets plug (-4) instead of y in (1)
-8x + 8y = -16 ------ (1)
-8x + 8(-4) = -16
-8x -32 = -16
-8x = 16
x = 16/(-8)
x = -2

so....
x= (-2) and y = (-4)

hope this will help ya :)

Answer 2

Have you made an attempt?
Where are you lost? I will provide an example and steps so you can learn how to do this.

The general steps are to solve one of the equations for either "x =" or "y =".

So say you have:
3y - 2x = 11
y + 2x = 9

3y - 2x = 11
y = 9 - 2x

So replace the "y" value in the first equation by what "y" now equals.
3(9 - 2x) - 2x = 11

Solve this new equation for "x".


(27 - 6x) - 2x = 11
27 - 6x - 2x = 11
27 - 8x = 11
-8x = -16
x = 2

Place this new "x" value into either of the ORIGINAL equations in order to solve for "y".
y + 2x = 9 or
y = 9 - 2x
y = 9 - 2(2)
y = 9 - 4
y = 5

So we know that:
x = 2 and y = 5

You can now check your answer, but substituting in the new found variables.

3y - 2x = 11
3(5) - 2(2) = 11
15 - 4 = 11
11 = 11 \(\huge\color{red}☑\)

y + 2x = 9
5 + 2(2) = 9
5 + 4 = 9
9 = 9 \(\huge\color{red}☑\)