OpenStudy (ajanijones):

A marble is drawn from a bag containing 3 red marbles and 2 blue marbles and a number cube with faces numbered 1 through 6 is tossed. What is the probability that the marble drawn is blue and the number cube shows a number less than 3? A.11/15 B.1/4 C.1/6 D. 2/15

3 years ago
OpenStudy (anonymous):

What is the First Rule to consider? Are the events of drawing a marble and tossing a a cube independent or dependent events?

3 years ago
OpenStudy (ajanijones):

Im not sure.

3 years ago
OpenStudy (anonymous):

Lets look at the Rule: Independent events = the outcome of the first event does not influence the outcome of the second event Dependent events= the outcome of the first event influences the outcome of the second event

3 years ago
OpenStudy (ajanijones):

I know all that i just think my answers wrong i got C.

3 years ago
OpenStudy (anonymous):

The events are independent...drawing a marble is completely separate from tossing the cube

3 years ago
OpenStudy (anonymous):

RULE: To determining the PROBABILITY OF TWO INDEPENDENT EVENTS: Probability that one event AND a second independent event will occur = Probability of desired event #1 occurring x Probability of desired event #2 occurring

3 years ago
OpenStudy (anonymous):

Probability of a desired event occurring = Number of desired outcomes / Number of possible outcomes

3 years ago
OpenStudy (ajanijones):

so whats the answer.

3 years ago
OpenStudy (anonymous):

Probability of desired event #1 occurring (DRAWING A BLUE MARBLE) = Number of desired outcomes (2 BLUE MARBLES)/Number of possible outcomes (5 TOTAL MARBLES) = 2/5

3 years ago
OpenStudy (anonymous):

I am explaining it step by step so you can answer any problem like this

3 years ago
OpenStudy (ajanijones):

I know the steps but i got wrong answer i think i got C. is that right or wrong. :(

3 years ago
OpenStudy (anonymous):

I have to work through the steps to get to the answer

3 years ago
OpenStudy (anonymous):

Probability of desired event #2 occurring (GETTING A #1 OR #2 ON CUBE) = Number of desired outcomes (2)/Number of possible outcomes (6 TOTAL FACES) = 2/6

3 years ago
OpenStudy (anonymous):

Probability of desired event #1 occurring x Probability of desired event #2 occurring =

3 years ago
OpenStudy (anonymous):

Now just plug into this equation the values I got for "Probability of event #1" and "Probability of event #2"!

3 years ago
OpenStudy (ajanijones):

so my answers A. :)

3 years ago
OpenStudy (anonymous):

What is the Probability of event #1 occurring (DRAWING A BLUE MARBLE)?

3 years ago
OpenStudy (ajanijones):

2/5

3 years ago
OpenStudy (anonymous):

good!

3 years ago
OpenStudy (anonymous):

Whats the Probability of desired event #2 occurring (GETTING A #1 OR #2 ON CUBE) ?

3 years ago
OpenStudy (anonymous):

Now just plug into this equation the values I got for "Probability of event #1" and "Probability of event #2"!

3 years ago
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