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integral of (ln(lnx))/(x)
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yes misprint on first one
was on phone had to repost
Let \(\Large\bf\sf u=\ln x\) Oh oh, if we rewrite our integral like this,\[\Large\bf\sf \int\limits \frac{\ln(\ln x)}{x}dx\quad=\quad \int\limits \ln(\ln x)\left(\frac{1}{x}dx\right)\]It might be easier to see what's going on.
ok
partial fractions?
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no sorry
integration by parts
\[\Large\bf\sf\int\limits\limits \ln(\color{royalblue}{\ln x})\left(\color{orangered}{\frac{1}{x}dx}\right)\]Are you able to find your du ok?\[\Large\bf\sf \color{royalblue}{u=\ln x}\]
Yes after you get your u-integral setup, you'll need to apply Integration-By-Parts.
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