Question

integrate tanx^4 sec x^3

Answer 1

If you remember
\[(secx)' = \tan(x)\sec(x)\]
In this case you have a composite function (exponentials) instead of just a regular x.

Answer 2

Wait, is this
\[\int\limits_{}^{} \tan^4 x \sec^3x dx\]
or
\[\int\limits_{}^{} \tan(x^4) \sec(x^3) dx\]

Answer 3

first one

Answer 4

I wish it was the second one

Answer 5

forgot the ( )

Answer 6

You can rewrite it as:
\[\int\limits_{}^{} \tan^2(x)* \tan^2(x) * \sec^2 (x) * \sec(x) dx\]
and
since
\[\sec^2(x) = 1 + \tan^2 (x)\]
from here it's just u-sub..

Answer 7

using identity right

Answer 8

yes that was a trig identity.

Answer 9

thx was just stump been a min I looked over this

Answer 10

you're welcome :)