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Find the limit as x approaches 0 of (3x-sin(kx))/x k can not = 0
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\(\bf lim_{x\to 0}\quad \cfrac{3x-sin(kx)}{x}\qquad \textit{multiply by "k"} \\ \quad \\ \cfrac{3x-sin(kx)}{x}\cdot \cfrac{k}{k}\implies \cfrac{3kx-sin(kx)k}{kx}\implies \cfrac{3kx}{kx}-\cfrac{sin(kx)k}{kx} \\ \quad \\ \cfrac{3kx}{kx}-\cfrac{sin(kx)}{kx}\cdot k\) what do you think?
\[\LARGE lim_{x \rightarrow 0}{\dfrac {3x-\sin(kx)}{x}}\]
is that the problem?
\(\LARGE lim_{x \rightarrow 0} {3x\over x} -lim_{x \rightarrow 0} {sin(kx)\over x}\)
\(\LARGE 3 -lim_{x \rightarrow 0} {kcos(kx)\over 1}=k\)
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