Heat Energy & Law of Thermodynamics Question:
A 0.200-kg piece of lead at 100.0°C is dropped into a calorimeter. The calorimeter is a copper can of mass 5.00  10–2 kg and already contains 0.100 kg of water at 20.0°C. Calculate the final temperature if the specific heats of water, lead, and copper are 4.20  103 J/kg K, 1.30  102 J/kg K, and 4.00  102 J/kg K respectively.

If someone could help work me through it, that would be great :)

Question

Heat Energy & Law of Thermodynamics Question:
A 0.200-kg piece of lead at 100.0°C is dropped into a calorimeter. The calorimeter is a copper can of mass 5.00  10–2 kg and already contains 0.100 kg of water at 20.0°C. Calculate the final temperature if the specific heats of water, lead, and copper are 4.20  103 J/kg K, 1.30  102 J/kg K, and 4.00  102 J/kg K respectively.

If someone could help work me through it, that would be great :)

anonymous · Answer

Two words 

Conservation of energy 
that is the principle of calorimeter!

anonymous · Answer

What formulas and how do I use them to solve for this?

anonymous · Answer

you think .. 
lets say the final temperature is t
can u tell me whether t will be more than 100 or less than 100 more than 20  or less than 20?

anonymous · Answer

Less than 100 and more than 20

anonymous · Answer

I guess

anonymous · Answer

I just don't know where to start with it or how to go about solving it

anonymous · Answer

My teacher told us that we were to find the Q for the calorimeter and the water add them then solve for the T sub F using the lead's specific heat and mass.

anonymous · Answer

But that didn't give me the answer he had on the board

wolfe8 · Answer

If you show what you worked and obtained, people can point out what is the problem.

raffle_snaffle · Answer

|dw:1393565259888:dw|

anonymous · Answer

Ok, I did this:
Q=(.1)(20)(4.2x10^3)=8400
Q=(5.0x10^-2)(20)(4x10^2)=400
8400+400= 8800
8800=(T)(.2)(1.3x10^2)
338.46=T

anonymous · Answer

I might've made a small calculation error, but does the core of it seem right? I could try fiddling with the numbers. I accidentally added 8400 and 400 and got 84400 (stupid, I know). I also didn't write down the correct answers for the problems, so I'm not sure if I have the right answer now.

anonymous · Answer

I'm fairly certain the answer is something like 2.22x10^4
Also, Are you guys still there?

raffle_snaffle · Answer

I am still here. Error could possibly be a rounding error, but that doesn't matter too much

anonymous · Answer

Does the work seem right though? It's 1 in the morning and I want to go to bed.

anonymous · Answer

Yeah, decided I don't care enough for this, I have a B in the class gd'nuff. Thanks for sitting on my question and yet saying nothing. :/

anonymous · Answer

Not to you, raffle, to the other two

raffle_snaffle · Answer

np=)