Question

Derivatives question:

Answer 1

Does:
\[\LARGE \frac{d}{dx}sec^2x=\frac{d}{dx}tan^2x\]

Answer 2

How did you get that?

Answer 3

If it were true, that would mean that: \[
\sec^2(x) - \tan^2(x) = C
\]

Answer 4

no.....dtan^2x/dx=2tanx*sec^2x

Answer 5

sorry yes

Answer 6

Did you use the Pythagorean property, or did you directly differentiate?

Answer 7

It was a quiz question, I was curious.

Answer 8

\[\sec ^2x -\tan ^2x=1\]

Answer 9

You could differentiate both sides of:\[
1+\tan^2(x)=\sec^2(x)
\]

Answer 10

differentianting
\[\frac{ d(\sec^2x-\tan^2x) }{ dx }=\frac{ d (1) }{ dx}=0\]

Answer 11

\[\frac{ d \sec^2x }{ dx } - \frac{ d \tan^2x }{ dx }=0\]

Answer 12

@Luigi0210