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\[\Huge y=e^{9\sqrt{x}}\]
By the chain rule:\[f(x)=e^{g(x)}~~\Rightarrow~~f'(x)=e^{g(x)}\cdot g'(x)\]
In this case, \(g(x)=9\sqrt x\), so \(g'(x)=\dfrac{9}{2\sqrt x}\). Also, \(f'(x)=\dfrac{dy}{dx}\). Just a notation preference.
So it'd pretty much be.. \[\Huge \frac{9*e^{9\sqrt{x}}}{2\sqrt{x}}\]
correct @Luigi0210
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Yes! Thank you for the clarification~
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