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Mathematics 11 Online
OpenStudy (luigi0210):

Find dy/dx

OpenStudy (luigi0210):

\[\Huge y=e^{9\sqrt{x}}\]

OpenStudy (anonymous):

By the chain rule:\[f(x)=e^{g(x)}~~\Rightarrow~~f'(x)=e^{g(x)}\cdot g'(x)\]

OpenStudy (anonymous):

In this case, \(g(x)=9\sqrt x\), so \(g'(x)=\dfrac{9}{2\sqrt x}\). Also, \(f'(x)=\dfrac{dy}{dx}\). Just a notation preference.

OpenStudy (luigi0210):

So it'd pretty much be.. \[\Huge \frac{9*e^{9\sqrt{x}}}{2\sqrt{x}}\]

OpenStudy (nincompoop):

correct @Luigi0210

OpenStudy (luigi0210):

Yes! Thank you for the clarification~

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