Question

Derivatives:

Answer 1

Find the 45th derivative of:
\[\LARGE y=cos(2x)\]

Answer 2

Ooo interesting problem :o

Answer 3

laughing out loud
here's the trick, at the 4th derivative it goes back to original function

Answer 4

if you don't believe me, try it

Answer 5

Well the sign/cosine go back to the start.
We keep getting factors of 2 though.
So it won't be exactly the same :)

Answer 6

Yup, it's that 2 that's the problem~

Answer 7

So the 0th derivative has a 2^0 in front, yes?

Answer 8

How bout the first derivative?
2^1?

Answer 9

What do you think for the 45th? ;D

Answer 10

Don't you have to bring the 2 out in front tho? o_O

Answer 11

\[\Large\bf\sf y0=\cos(2x)\]\[\Large\bf\sf y1=2(-\sin(2x))\]\[\Large\bf\sf y2=2^2(-\cos(2x))\]

Answer 12

What do you mean igi? :o

Answer 13

you would put something in the front
blah blah blah sin(2x)

Answer 14

-2^45 sin(2x)

Answer 15

Whoops, I mis-interpreted you guys.
What I was trying to say is what you and nin just said

Answer 16

lameeee +_+ you gave the answer.

Answer 17

laughing out loud

Answer 18

At least I know how he got it tho :3

Answer 19

ok good c:

Answer 20

I usually don't do this, but I don't want him to actually put 2x2x2x2.....

Answer 21

Do you though? c:
Do you understand what he was saying with the multiples of 4 thing?

Answer 22

Yea, nin saved me time xD

Answer 23

someone is late in the game

Answer 24

Thanks guys :)