Question

Find the Limit as x approaches infinity.
Sqrt(x^2-3x)-x?
I know the answer is 1.5 I just don't know how to reach that...the right way

Answer 1

multiply by
\[\frac{\sqrt{x^2-3x}+x}{\sqrt{x^2-3x}+x}\]

Answer 2

haha, oh wow, thank you :)

Answer 3

you get
\[\frac{x^2-3x-x^2}{\sqrt{x^2-3x}+x}\] or
\[\frac{-3x}{\sqrt{x^2-3x}+x}\]

Answer 4

yw

Answer 5

i actually get \(-1.5\) though