Point C is located at (1, 2) and point D is located at (−4, −2). Find the y value of the point that is 1 over 4 the distance from point C to point D. 1 0 1.5 2.25
you want to find the equation to the line first. You can do that with the slope and the y intercept
the slope (rise/run) will be the y values of C and D (2 and -2) divided by the x values of C and D (1 and -4)
so it will be 2-(-2) or 4 divided by 1-(-4) or 5 so 4/5 will be your slope
the slope is the rate of change of x...since the equation is a line, it will be y=4/5x + b (b is the y intercept
sorry, this is a lot :/
it ok its really helpful thankyou
alrighty :)
plug in one of your points ( C or D) into your almost equation ( y = 4/5 x + b)
lets say (1,2) so (2) = 4/5*(1) + b and you solve for b
b will end up being 1 and 1/5 because 2-4/5=1and1/5
so your equation is y=4/5x+6/5
I'm sorry @Kali_s this is super long... do you know pythagorean theorum?
yes is do
i*
sweet! so the bottom side will be 5 and the right side will be 4
4^2 + 5^2 = c^2 16 + 25 = 41 = c^2 so c = Sqrt(41) so you follow that?
yeaah
cool :)
sqrt(41) is the distance between the two points.
sorry @Kali_s, ignore that last one..man, you're very patient, multiply 1/4 by the whole y distance. or 4
i like to learn lol and you're helping me out a lot believe me(:
Because the total rise is 4, so 1/4 of the rise will be just 1 :)
Since point C is (1,2) you want to add 1 to the y part then plug it in to your equation so plug 3 into the Y of your equation and solve (x,3) or 3 = 4/5x + 6/5
WOW
It's asking for the Y value so you already have it :)
We know that when y=3 it is 1/4 from point C to point D SOO, your answer is 3 :D
Thanks for your patience @Kali_s!
welcomee! and thankyou soo much...
:)
@Josh55 3 isnt one of my answer choices:(
oh dear
yeah
oh, the slope is negative so instead of 2 + 1 being three, it is 2 - 1 so the answer is 1 instead :)
thankyou soo much
haha, you're so patient, Thank You :) I will be more patient with people around ME in the future :)
lol no problem
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