Question

Which shows this equation in standard form?

7 – 3(x – y) = 5x + 2
A.
3x – 8y = 5

B.
8x + 3y = 5

C.
8x – 3y = 5

D.
8x – 3y = –5

Answer 1

The key to "solving" this problem lies in knowing what a linear equation in standard form looks like: Ax+By=C.

So, if we have 7 – 3(x – y) = 5x + 2, we'll need to perform the indicated multiplication first, and then combine like terms, and, finally, to rearrange the terms with the variable x and its coefficient first, the var. y and its coeff. second, and the constant on the right of the equation.

Mind starting by multiplying out that -3(x-y) in 7 – 3(x – y) = 5x + 2 ?

Answer 2

ok. then what.

Answer 3

why

Answer 4

oh. HE wanted me to answer it. Ok. I didnt get that. Thanks

Answer 5

thnaks

Answer 6

Yes, I'm always looking for ways to help OpenStudy participants learn to find their own answers, with guidance and positive reinforcement.

7 – 3(x – y) = 5x + 2 should be "expanded," which, as I said before, involves multiplying out -3(x-y).

-3(x-y) = - 3x + 3y

So now you have

7 – 3x + 3y = 5x + 2

Please, @gymnast13, show your stuff here: Combine the like terms.

When you've done that, rearrange your expression to look like

Ax + By = C.