Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

2 questions? Look below. Medal/fan to first person who answers!

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

@kewlgeek555

OpenStudy (anonymous):

@timo86m

OpenStudy (mathmale):

So you'd like for us to focus on that "average rate of change" problem (#4)?

OpenStudy (anonymous):

and the other one too. #5, i changed the previous one. I need both #4 and 5

OpenStudy (anonymous):

if you only know #4 then thats fine

OpenStudy (mathmale):

Please post just one problem at a time, so potential helpers don't need to ask you which one you want to discuss. The formula for "average rate of change" is \[a.v.r.=\frac{ f(b)-f(a) }{ b-a }\] You don't know what f(x) is, but the graph tells you all you need to know. to find out where you're coming from: please identify the values of a and b from the graph.

OpenStudy (anonymous):

1 and -2 are the only points. so i guess they are a and b

OpenStudy (mathmale):

Prefer you know, rather than guess! Please read the instructions for #4. What do they say? I ask because 1 and -2 are not the values of a and b.

OpenStudy (anonymous):

Using the graph, Calculate the average rate of change from x=0 to x=2.

OpenStudy (anonymous):

for f(x)

OpenStudy (mathmale):

The question asks you to calculate the average value of the function for which the graph is given, on the interval [0,2]. With this in mind, please identify the values of a and b.

OpenStudy (anonymous):

what does "the interval 0,2" mean

OpenStudy (anonymous):

I think first we need to know the equation.

OpenStudy (mathmale):

I'm afraid we'd have to go back and review several key concepts before this is going to make sense to you. Have you any examples at all of "finding the average value of a function" to which you could refer? Do you hae the time and are you willing to go over the background material before we try to answer this present question? I would hope that you'd understand what "interval" means in this context.

OpenStudy (anonymous):

why can't you just explain it

OpenStudy (anonymous):

I just wanted someone to write out how to do this, show me step by step

OpenStudy (anonymous):

I think your making it too complicated then it already is. because in my lesson, we don't use the word interval.

OpenStudy (anonymous):

@aprilann143 can you help with #5? or #4?

OpenStudy (anonymous):

we are just supposed to use slope for this, not any complicated formula.

OpenStudy (mathmale):

going through the problem step by step won't do you much good if you don't already understand the concept of "interval" and that if the interval is [0,2], a=0 and b=2. I see you've chosen to address my concerns by going elsewhere. If you'd like to resume work on this problem with me later, message me.

OpenStudy (anonymous):

oh, i get that now

OpenStudy (anonymous):

so x= 0, x= 2, just means the interval (0,2). that's also called a point u know

OpenStudy (mathmale):

The formula I gave you for the average rate of change is the proper formula, and it does represent the slope of a line. I'll give you a couple of clues: a=0, the left end of your interval. b=2, the right end of your interval. What is b-a? Now look at the graph. When a=0, what is f(a)? Hint: when x=0, what is f(0)?

OpenStudy (mathmale):

As before, I ask you to re-read the problem statement. That statement says, "from 0 to 2." That's your interval. Your a=0 and your b=2. You will definitely need to know this in the future.

OpenStudy (anonymous):

oh

OpenStudy (mathmale):

So, if we are to move from 0 to 2, a=0 and b=2, and b-a=2-0=2, right?

OpenStudy (mathmale):

a-b=-2, but I asked for b-a=2.

OpenStudy (mathmale):

Now copy down the formula I gave you. Replace "b-a" by 2, ok?

OpenStudy (anonymous):

done

OpenStudy (mathmale):

Now, plese look at that graph again. we need to find the value of f(x) when x = a = 0. If x=0, y appears to be .... what value?

OpenStudy (anonymous):

uhh

OpenStudy (anonymous):

r u talking about a point already on the graph or no

OpenStudy (mathmale):

Actually, it's simply the point on the graph where x=0. It happens that x=0 is the y-axis. At what value of y does the graph cross the y-axis?

OpenStudy (anonymous):

-2

OpenStudy (mathmale):

that's it. so, if a=0, f(a)=f(0)=-2. Replace your f(a) in that formula by -2 now, please.

OpenStudy (anonymous):

done

OpenStudy (anonymous):

hey

OpenStudy (anonymous):

Btw, the choices are: A. x= -4 B. x= -2 C. x= 2 D. x= 4

OpenStudy (anonymous):

wat dos Btw mean

OpenStudy (anonymous):

by the way.

OpenStudy (anonymous):

ok

OpenStudy (mathmale):

\[a.v.=\frac{ f(b)-(-2)) }{ 2 }\] is what you should now have. do you have that?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

"what's a calcular"... wat wer u saying

OpenStudy (anonymous):

look at ur name...

OpenStudy (anonymous):

yea is it bad?

OpenStudy (anonymous):

did you misspell it? maybe you meant to write "calculator"

OpenStudy (anonymous):

No, I spelled it correctly. That is how Open Study spelled it. lol

OpenStudy (anonymous):

weird

OpenStudy (anonymous):

yea do u need help with a question?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!