Please helpppp! ):

Question

Please helpppp! ):

anonymous · Answer

attachment

anonymous · Answer

@Mertsj

mertsj · Answer

What do you mean by an "explicit definition"?

anonymous · Answer

i have no clue to be honest…I'm so lost with this stuff

mertsj · Answer

I don't know either.  Look at your book and tell me what it says.

anonymous · Answer

i found "explicit formula" but no "explicit definition"

anonymous · Answer

@Mertsj

mertsj · Answer

So I think I have found out that those are all explicit definitions and we have to pick the one that works for that sequence of numbers.

mertsj · Answer

So we have to find which rule works.  n is the number of the term.

mertsj · Answer

The third term is 6 so let's try n = 3  in the first answer.

mertsj · Answer

$$a _{3}=6=-4+5(3+1)$$
$$6=-4+5(4)$$
$$6=-4+20=16$$

mertsj · Answer

That doesn't work.  So it is not choice a

mertsj · Answer

Let's try choice b

mertsj · Answer

$$a _{3}=6=-4+5(3-1)$$
$$6=-4+5(2)$$
$$6=-4+10=6$$

mertsj · Answer

That seems to work.  Try it with the second term.  In other words, n = 2.  See if it works for the second term.

anonymous · Answer

I hope I'm not throwing you off track but why did you choose to use the third term?

anonymous · Answer

@Mertsj

mertsj · Answer

I thought 6 was an easy number to work with.

mertsj · Answer

Did it work for the second term?

anonymous · Answer

ok i didn't know if that was something you had to do or not! and I'm about to try and find out idk how to do this really I'm kinda new but I'm gonna try!

mertsj · Answer

ok good

anonymous · Answer

It seems to work! i got 1=1 @Mertsj

mertsj · Answer

Good.  You could try the other terms if you wanted, or just choose that answer.