Question

Find dy/dx for y=(3x^2-x)/(4x^3)

Answer 1

\(\bf \textit{use the quoutient rule} \cfrac{d}{dx}\left[\cfrac{f(x)}{g(x)}\right]\implies \cfrac{f'(x)g(x)-f(x)g'(x)}{g(x)^2}\)

Answer 2

So, it is just like a normal derivative? Or is there some other procedure because they said dy/dx?

Answer 3

dy/dx = derivative

Answer 4

is just another way to write it, yet another way would be \(\bf \cfrac{\Delta y}{\Delta x}\implies \cfrac{dy}{dx}\) recall that Delta is usually used for "rates of change"

Answer 5

yea, but I thought the normal derivative was d/dx. Isn't it implicit differentiation when its dy/dx or something?

Answer 6

no as far as I know
dy/dx is just another notation for a derivative