Question

ay=-9.8m/s2 v1y=0m/s ∆dy=-91.2cm (-0.912m)±1.5mm (0.0015m) ∆t=?
∆dy= v1y∆t + 1/2ay∆t2
-0.912m±0.0015m=0∆t + 1/2(-9.8m/s2)∆t2
-0.912m±0.0015m=-4.9m/s2∆t2
0.1861224499s2±0.16%=∆t2
√0.186122449s2±0.16%=√∆t2
0.43141911s±0.4%=∆t
0.43s±0s=∆t
Is this correct?