Write the standard equation of the circle.

Question

highschoolmom2010 · Answer

i am to the point of (x-2)^2+(y-2)^2=r^2 
not i need to figure out where to go from here

isaiah.feynman · Answer

What's r?

highschoolmom2010 · Answer

i have to find the x and y values to get r but on that graph its unclear exactly where the circle falls to give a value to give a value to them....

isaiah.feynman · Answer

No. You don't need x and y. R is simply 5. From the graph.

highschoolmom2010 · Answer

ok you gotta explain where you see 5 at because im definitely not seeing that

isaiah.feynman · Answer

Sorry not 5, but 4. I read wrong.

highschoolmom2010 · Answer

i still have to technically give  a point and work the equation to prove it is 4 -_-

highschoolmom2010 · Answer

so i guess ill put (2,6)

highschoolmom2010 · Answer

ok yea that works

isaiah.feynman · Answer

The radius is not a point. Its a line. |dw:1393621839427:dw|

highschoolmom2010 · Answer

thanks @Isaiah.Feynman  :D

isaiah.feynman · Answer

Good for you.

phi · Answer

It looks like you found r=4  (by counting straight up from the center, for example)
so the equation is
$$ (x-2)^2 + (y-2)^2 = 16 $$
as you can see, most of the points are hard to read off the graph, but 4 of them are easy: (-2,2), (2,6), (2,-2), (6,2)
that you can use to show the equation is correct.