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OpenStudy (anonymous):
What is the volume of the right cone shown below?
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OpenStudy (jdoe0001):
0, since the cone is blank
OpenStudy (anonymous):
OpenStudy (anonymous):
@jdoe0001 help now?
OpenStudy (jdoe0001):
\(\bf \textit{volume of a cone} =\cfrac{\pi r^2 h}{3}
\\ \quad \\
h = height\qquad \qquad r = radius = \frac{diameter}{2}\)
OpenStudy (anonymous):
can youplug them in for me?
h=27 R=6
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OpenStudy (anonymous):
i dont know what i do from here
OpenStudy (jdoe0001):
well.. what's the radius?
OpenStudy (anonymous):
3.14*6?
OpenStudy (jdoe0001):
do you know what a radius is?
OpenStudy (anonymous):
on my cone on the picture the radius would be 6 half of 12
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OpenStudy (jdoe0001):
\(\bf \textit{volume of a cone} =\cfrac{\pi \cdot {\color{red}{ 6}}^2 \cdot 27}{3}
\\ \quad \\
h = height\qquad \qquad r = 6 = \frac{12}{2}\)
OpenStudy (anonymous):
508.68?
OpenStudy (jdoe0001):
\(\bf \textit{volume of a cone} =\cfrac{\pi \cdot {\color{red}{ 6}}^2 \cdot 27}{3}\implies \cfrac{36\cdot 27}{3}\ \pi\)
OpenStudy (anonymous):
972π units3?
OpenStudy (jdoe0001):
well, what about the denominator though? you still need to divide the product by that
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OpenStudy (jdoe0001):
\(\bf \textit{volume of a cone} =\cfrac{\pi \cdot {\color{red}{ 6}}^2 \cdot 27}{3}\implies \cfrac{36\cdot 27}{3}\ \pi\implies \cfrac{972}{3}\ \pi\)
OpenStudy (anonymous):
324πunits3?
OpenStudy (jdoe0001):
324πunits3? \(\checkmark\)
OpenStudy (anonymous):
ty so much
OpenStudy (jdoe0001):
yw
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