Question

What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1, 5)?



y = -3/2x + 7/2

2y = -3x + 7

2x + 3y - 7 = 0

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ 3}}\quad ,&{\color{blue}{ -1}})\quad &({\color{red}{ -1}}\quad ,&{\color{blue}{ 5}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form} \)

Answer 2

so A?

Answer 3

well, what did you get for the slope?

Answer 4

1?

Answer 5

well, try plugging in the values for the rise and run, see what you get for the slope