A 200.0 g copper block absorbs 2.34 × 10^3 J of heat to raise its temperature by 30.0 K. What is the specific heat of copper? Is it 234 something?
@greenleaf800073
\[\Delta T\]=30K mass = 200g Q = 2340J C = 2340J/(200g * 30K) C = .39 J/g * K
T = change in temperature Q = applied energy C = specific heat C = Q/(mass * T)
awesome
Heat added = specific heat x mass x (t final - t initial) 2340J = specific heat * 0.2 kg * (50K - 20K) Cu specific heat = 0.39 J /g C
great!
A 500.0 g metal block absorbs 3.25 × 103 J of heat to raise its temperature by 50.0 K. What is the substance?
is this one also asking for specific heat?
Heat added = specific heat x mass x (t final - t initial) 3250 J = specific heat * 0.5 kg * ( 70K - 20K) specific heat = 0.13 J /g C Looking at a table, Tungsten has 0.134 J /g C , specific heat
Sorry ..i mean lead, using your chart
Since it is easy to find the specific heat with the formula above, you then take that number calculated and compare it to the chart you posted
awesome thanks!! :)
@roadjester
its the one about the 500 g metal block
with the substance table
what is the variable you're unsure of?
is it 0.13 J/ g x C or 0.13 j/Kg. K?
/Kg x K
he used 0.5 kg so i was curious
was the original answer correct or was the unit supposed to be written with the kg x K? because on the table there are two ways of writing it at the top
looks like this might take some time and its 2am where i live so i can just come back in a few hours
It depends, As long as you are consistent and have a unit of energy divided by a unit of mass and unit of temperature, it's correct.
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