A car moving at a speed of 20 m/s, then accelerates uniformly at 1.8m/s^2 until it reaches a speed of 25m/s What distance does it travel during the time it is accelerating?

Question

A car moving at a speed of 20 m/s, then accelerates uniformly at 1.8m/s^2 until it reaches a speed of 25m/s  What distance does it travel during the time it is accelerating?

anonymous · Answer

btw, are you doing your homework? XD

25 m/s - 20 m/s = 5 m/s, 5 m/s / 1.8 m/s^2 = 2.7777778 s

D = Vit + 1/2at^2
D = 20 m/s * 2.778 s + 1.8 m/s^2 * (2.778s)^2
D = 55.56m + 5.0004m
D = 60.5604m

anonymous · Answer

0.16 m/s2
	0.20 m/s2
	0.14 m/s2
	0.19 m/s2
	0.17 m/s2
? I'm sorry but tbh physics is harddddd

anonymous · Answer

???? it asks for the distance, why are the options in acceleration?

anonymous · Answer

wrong answers haha these are 
58 m
	50 m
	54 m
	66 m
	62 m

anonymous · Answer

.-. closest answer is 62m

anonymous · Answer

Thank you XD