Question

Help me I don't understand this derivation http://goo.gl/pJ1XTp

Answer 1

give me the complete solution !

Answer 2

Without knowing the context in which you found these relationships, or what the instructions for this math problem are, it's hard to give you meaningful feedback. Where did this content come from? What are you supposed to do here? How familiar are you with partial derivatives?

Answer 3

sorry, my bad that I didn't explain the context,
here, http://s13.postimg.org/slwizp4zr/help1.png
the first row is the formula i got from my physic lab to calculate heat capacity
the second row is the formula to find 'errors' of heat capacity
the last row is my friend's solution and what the answer i need should look like.
the problem is I don't know if my friend do the derivation correctly or not.
can someone check/correct it for me?

Answer 4

this is easy

Answer 5

I'd love to help, but these partial derivatives are not something I could explain in a few minutes' time. Your course content is far beyond most of the problems posted here on OpenStudy.

Also, I'd be much more comfortable responding to what you yourself have done (I'd like to see your actual work); I'd rather not "check your friend's work."

Answer 6

break it into parts and then see what you can do from that point

Answer 7

i know, i do understand derivation basic. But I'm just new to this kind of formula, so I just want someone to check it for me because I and my friend get stuck here.

Answer 8

even physics follow mathematical principles
immediately, heat capacity uses constants you can always extract it out

Answer 9

Ta - Tm is the change in temperature

Answer 10

I'm sorry, Hansenjordan, but this kind of problem is beyond what I'm able to do here in a reasonable amount of time. Don't get me wrong; I'd love to help. I'd suggest you just leave your question posted; it will be automatically bumped to the top of the question queue in 5-10 minutes. Perhaps someone else more familiar with the content here will respond. Is there any chance that your own teacher could help you with this problem?

Answer 11

let us start with
Q = cm(delta T)

Answer 12

Hanshenjordan: I'm really sorry, but will not be responding further to your question, for the reasons I gave you. Best wishes / good luck to you!

Answer 13

how many materials are involved?
because it is necessary to include other metals other than what you are observing when performing an experiment. they, too, absorb heat and expand.

Answer 14

from the subscripts, I am thinking there are 4

Answer 15

@mathmale alright, it's ok, your response is highly appreciated. yes my teacher can help me, but I'm not in the lab right now, this is part of my lab report that need to be submitted in the next meeting. So i have no time to ask my teacher until i submit this. I'm just trying to study it here. :)

Answer 16

@nincompoop emm i think i just need the errors formula answer after being derivated. and yes i don't understand how to do the dCk/dTa

Answer 17

I did the same experiment last year, but without this type of derivation. I, however, used a table for known specific heat and heat capacity of various materials I've used for the experiment.

Answer 18

@nincompoop i see. did you also have this kind of errors calculation back then?

Answer 19

if you can tell me the materials/metals involved, I can perhaps give a clearer extrapolation

Answer 20

it was slight of an error, because my experiment was properly insulated so no significant heat was escaping

Answer 21

@nincompoop i used iron, brass, and aluminium in my lab here.

Answer 22

hmm but I think there is no relation between the errors formula and the materials i used

Answer 23

the errors formula is a general equation used in my lab. it is used in any kind of experiment, the difference is only on the variable used.

Answer 24

I'm making report for my physic lab. The think is this errors formula is an obligation in the report. So i need to do this calculation to continue.

Answer 25

there is no error formula. the error comes in when comparing experimental and theoretical
(experimental value - theoretical value)/theoretical x 100

Answer 26

I don't know how to say it. I just translate it as 'errors' from my native language. I'm aware it may not be called 'errors' in english. This formula is given by my teachers, I just confused on how to call it now. So I just need to do the derivation now. Can you help me please?