Question

Is my proof correct? (0=1)?

Answer 1

\[0=0+0+0+0+...\]
\[0=(1-1)+(1-1)+(1-1)+...\]
\[0=1-1+1-1+1-1+...\]
\[0=1+(-1+1)+(-1+1)+(-1+1)+...\]
Therefore:
\[0=1\]

Answer 2

no

Answer 3

Well, why?

Answer 4

any proof that gets the wrong result isn't correct. :P

Answer 5

From what I see, it's not the best way to handle a divergent series.

Answer 6

hahaha.... its absolutely wrong

Answer 7

is this a joke?:D

Answer 8

wasting threads!!

Answer 9

Well, I see no justifications, so I don't think so.

Answer 10

see, if we have odd like 5 ones :-
\[\huge \bf 0=1-1+1-1+1\]
\[\large \bf 0=1+(-1+1)+(-1+1)=\frac{0}{2}+0+0\]

Answer 11

is it correct ? @Owlcoffee

Answer 12

You're bringing a series that diverges, i.e., has no value.

Answer 13

x = y.
Then x2 = xy.
Subtract the same thing from both sides:
x2 - y2 = xy - y2.
Dividing by (x-y), obtain
x + y = y.
Since x = y, we see that
2 y = y.
Thus 2 = 1, since we started with y nonzero.
Subtracting 1 from both sides,
1 = 0.

Answer 14

hue hue hue

Answer 15

hope you understand

Answer 16

Wow, I don't want to see you guys to write a proof, ever.
I want solid arguements, not arrows and "Oh, duh, he's dumb".

Answer 17

he kinda sent the 1st 1 to the end of the series,,, :D

Answer 18

u cannot write a series like dat!

Answer 19

Dude between step 2 and 3, you can't just take the brackets away.

Answer 20

You start off with the supposition that (1 - 1) + (1 - 1) ... = 1 - 1 + 1 - 1 ...
This is an infinite series, and you can't change the order of computation.

Answer 21

^

Answer 22

you want solid arguments :-
here :-

first,
\[\large \bf 0=0+0+0+0+0\]
\[\large \bf 0=(1-1)+(1-1)+(1-1)+(1-1)+(1-1)\]
open brackets,
\[\large \bf 0=1-1+1-1+1-1+1-1+1-1\]
then, arrange it
\[\bf 0=1+(-1+1)+(-1+1)+(-1+1)+(-1+1)-1\]
\[\large \bf 0=1-1\]
\[\large \bf 0=0\]

Hence, Proved.

Answer 23

Let us assume

0 = 2

0 * 0 = 2 * 0 = 0

Thus, both of them are same? WE CANNOT SAY THAT! :D

Answer 24

hope you now understand. @Owlcoffee

Answer 25

Although if you want to a cool math trick, which is actually legitimate and is used with lorentzian transformations in spacetime events.

1 + 2 + 3 + 4 + 5..... = -1/12

Google it. :)

Answer 26

i have proved it. @AkashdeepDeb

Answer 27

in the style of owlcoffee

Answer 28

http://mathworld.wolfram.com/DivergentSeries.html

Answer 29

Sweg

Answer 30

Satisfied ? @Owlcoffee

Answer 31

Thank you.
I knew how it was all along, ir was just a way for me to evaluate how people view mathematics. It's a group proyect I have.